MCQ
The measures of $\angle\text{x}$ and $\angle\text{y}$ in Figure. are respectively:
- A$30^\circ , 60^\circ$
- B$40^\circ , 40^\circ$
- C$70^\circ , 70^\circ$
- ✓$70^\circ , 60^\circ$
As we know,
Measure of exterior angle = Sum of the opposite interior angles.
$\Rightarrow \ \angle\text{R}=\angle\text{P}+\angle\text{Q}$
$\Rightarrow \ 120^{0}=\text{x}+50^{0}$ $[\because \angle\text{R}=120^{0}]$
$\Rightarrow \ \text{x}=120^{0}-50^{0}$
$\Rightarrow \ \text{x}=70^{0}$
Now, the sum of the interior angles of a triangles is 180°.
$\therefore x + y + 50^\circ = 180^\circ $
$\Rightarrow 70^\circ + y + 50^\circ = 180^\circ $
$\Rightarrow 120^\circ + y = 180^\circ $
$\Rightarrow y = 180^\circ - 120^\circ $
$\Rightarrow y = 60^\circ $
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