MCQ
The middle term in the expression of ${\left( {x - \frac{1}{x}} \right)^{18}}$ is
- A$^{18}{C_9}$
- ✓${ - ^{18}}{C_9}$
- C$^{18}{C_0}$
- D${ - ^{18}}{C_{10}}$
$\therefore $Middle term is $10^{th}$ term.
==> ${T_{10}} = {}^{18}{C_9}{(x)^9}.\,{\left( { - \frac{1}{x}} \right)^9} = {\rm{ }} - {}^{18}{C_9}$.
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$1.$ The numbers $\left|A_1\right|,\left|A_2\right|, \ldots,\left|A_m\right|$ are distinct.
$2.$ $A_1, A_2, \ldots, A_m$ are pairwise disjoint.(Here $|A|$ donotes the number of elements in the set $A$ )Then, the maximum possible value of $m$ is