MCQ
The minimum frequency $\nu $ of continuous $X-$ rays is related to the applied potential difference $V$ as
- A$\nu \propto \sqrt V $
- ✓$\nu \propto V$
- C$\nu \propto {V^{3/2}}$
- D$\nu \propto {V^2}$
✓
Answer
Correct option: B.
$\nu \propto V$
b
(b)$E = h\nu = eV\, \Rightarrow \,\nu \propto V$
(b)$E = h\nu = eV\, \Rightarrow \,\nu \propto V$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Two springs with spring constants ${K_1} = 1500\,N/m$ and ${K_2} = 3000\,N/m$ are stretched by the same force. The ratio of potential energy stored in spring will be
→The $B-H$ curve for a ferromagnet is shown in the figure. The ferromagnet is placed inside a long solenoid with $1000\, turns/cm$ . The current that should be passed in the solenoid to demagnetise the ferromagnet completely is
→In finding out refractive index of glass slab the following observations were made through travelling microscope $50$ vernier scale division $= 49\ \text{MSD}; 20$ divisions on main scale in each $\ cm$ For mark on paper
$\text{MSR} = 8.45 \ cm, VC = 26$
For mark on paper seen through slab
$\text{MSR} = 7.12 \ cm, VC = 41$
For powder particle on the top surface of the glass slab
$\text{MSR} = 4.05 \ cm, VC = 1$
$(\text{MSR} =$ Main Scale Reading, $VC =$ Vernier Coincidence$)$
Refractive index of the glass slab is:
→$\text{MSR} = 8.45 \ cm, VC = 26$
For mark on paper seen through slab
$\text{MSR} = 7.12 \ cm, VC = 41$
For powder particle on the top surface of the glass slab
$\text{MSR} = 4.05 \ cm, VC = 1$
$(\text{MSR} =$ Main Scale Reading, $VC =$ Vernier Coincidence$)$
Refractive index of the glass slab is:
Moment of inertia of a rectangular plate about an axis passing through $P$ and perpendicular to the plate is $I$. Then moment of $PQR$ about an axis perpendicular to the plane of the plate:
→A particle is projected from the ground at an angle of $\theta $ with the horizontal with an initial speed of $u$. Time after which velocity vector of the projectile is perpendicular to the initial velocity is
→A parallel plate air capacitor is charged to a potential difference of $V$ volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates
→An assembly of identical spring-mass systems is placed on a smooth horizontal surface as shown. At this instant, the springs are relaxed. The left mass is displaced to the/left and theiright mass is displaced to the right by same distance and released. The resulting collision is elastic. The time period of the oscillations of system is
The figure shows a network of currents. The magnitude of currents is shown here. The current $I$ will be ........... $A$
→At what depth below the surface of the earth, acceleration due to gravity $g$ will be half its value $1600 \,km$ above the surface of the earth
→The strength of the magnetic field in which the magnet of a vibration magnetometer is oscillating is increased $4$ times its original value. The frequency of oscillation would then become
→