MCQ
The minimum wavelength of the $X$-rays produced at accelerating potential $V$ is $\lambda$. If the accelerating potential is changed to $2 \,V$, then the minimum wavelength would become
- A$4 \lambda$
- B$2 \lambda$
- ✓$\lambda / 2$
- D$\lambda / 4$
$\lambda_{\min }=\frac{12400}{V}$
If potential is changed to $2 \,V$
$\operatorname{New} \lambda_{\min }=\frac{\lambda}{2}$
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