MCQ
The minimum wavelength of the $X-$ rays produced by electrons accelerated through a potential difference of $V$ volts is directly proportional to
- A$\sqrt V $
- B${V^2}$
- C$1/\sqrt V $
- ✓$1/V$
✓
Answer
Correct option: D.
$1/V$
d
$h{\nu _{\max }} = eV$
$h{\nu _{\max }} = eV$
$ \Rightarrow \,\frac{{hc}}{{{\lambda _{\min }}}} = eV$
$\therefore \,\,{\lambda _{\min }} \propto \frac{1}{V}$
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