MCQ
The molality of $90\%$ ${H_2}S{O_4}$ solution is [density $=1.8\,gm/ml$ ]
- A$1.8$
- B$48.4$
- ✓$9.18$
- D$94.6$
✓
Answer
Correct option: C.
$9.18$
c
(c) The density of solution $ = 1.8\,gm/ml$
(c) The density of solution $ = 1.8\,gm/ml$
Weight of one litre of solution $ = 1800\,gm$
$\therefore $ Weight of ${H_2}S{O_4}$ in the solution$ = \frac{{1800 \times 90}}{{100}}$$=162\,gm$
$\therefore $ Weight of solvent $ = 1800 - 1620 = 180\,gm$
$\therefore $ Molality $ = \frac{{1620}}{{98}} \times \frac{{100}}{{180}} = 9.18$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In which orbit of the Bohr model of the hydrogen atom is the speed of electron maximum
The major product $Z$ obtained in the following reaction scheme is
→How many moles of ferric-alum $(NH_4)_2SO_4.Fe_2(SO_4)_3.24H_2O $ can be made from the sample of $Fe$ containing $0.0056\,g$ of it ?
→Identify the no. of $\alpha -\,$ Hydrogen in the given compound?
→The $\Delta H_f^o$ for $C{O_2}(g),\,CO(g)$ and ${H_2}O(g)$ are $-393.5, -110.5$ and $-241.8\,kJ\,mol^{-1}$ respectively. The standard enthalpy change (in $kJ$) for the reaction $C{O_2}(g) + {H_2}(g) \to $ $CO(g) + {H_2}O(g)$ is
→In the following reactions products $(A)$ and $(B)$. respectively, are
→$\mathrm{NaOH}+\mathrm{Cl}_{2} \rightarrow(\mathrm{A})+$ side products
(hot and conc.)
$\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{Cl}_{2} \rightarrow(\mathrm{B})+$ side products
$(dry)$
Standard entropy of $X_2, Y_2$ and $XY_3$ are $60, 40$ and $50\,J \,K^{-1}\,mol^{-1},$ respectively. For the reaction,
→$\frac{1}{2}{X_2} + \frac{3}{2}{Y_2} \to X{Y_3},\,\Delta H = - 30\,kJ$ , to be at equilibrium, the temperature will be ............... $\mathrm{K}$
Which element has the lowest electronegativity
In Friedel Craft's alkylation, besides $AlC{l_3}$ the other reactants are
→Which of the following orbital can not form $\pi$ as well as $\delta$ -Bond ?
→