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STD 12 - 2. Electrochemistry — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 2. Electrochemistry4 Marks
MCQ
The molar conductivities $\Lambda _{NaOH}^o$ and $\Lambda _{HCl}^o$ at infinite dilution in water at $25^o C$ are $91.0$ and $426.2\, S \,cm^2/mol$ respectively. To calculate $\Lambda _{HOAc}^o,$ the additional value required is
  • A
    $\Lambda _{NaOH}^o$
  • ✓
    $\Lambda _{NaCl}^o$
  • C
    $\Lambda _{{H_2}O}^o$
  • D
    $\Lambda _{KCl}^o$
✓

Answer

Correct option: B.
$\Lambda _{NaCl}^o$
b
$\Lambda_{C H_{3} C O O H}^{o}$ is given by the following equation

$\Lambda_{C H_{3} C O O H}^{o}=\left(\Lambda_{C H_{3} C O O N a}^{o}+\Lambda_{H C l}^{o}\right)-\left(\Lambda_{N a C l}^{o}\right)$

Hence $\Lambda_{N a C l}^{\circ}$ is required.

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