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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
The molar solubility $(mol\;{L^{ - 1}})$ of a sparingly soluble salt $M{X_4}$ is $'s'$. The corresponding solubility product is ${K_{sp}}$. $'s'$ is given in terms of $_{{K_{sp}}}$ by the relation
  • A
    $s = {(256{K_{sp}})^{1/5}}$
  • B
    $s = {(128{K_{sp}})^{1/4}}$
  • C
    $s = {({K_{sp}}/128)^{1/4}}$
  • ✓
    $s = {({K_{sp}}/256)^{1/5}}$
✓

Answer

Correct option: D.
$s = {({K_{sp}}/256)^{1/5}}$
(d) $M{X_4} \to \mathop M\limits_s + \mathop {4X}\limits_{4s} $ ;

${K_{sp}} = {(4s)^4}s$; ${K_{sp}} = 256{s^5}$

$s = {\left( {\frac{{{K_{sp}}}}{{256}}} \right)^{1/5}}$

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