- A$N\,-\,N$
- B$F\,-\,F$
- ✓$C\,-\,C$
- D$O\,-\,O$
In the given molecules fluorine, nitrogen and oxygen atoms have lone pair electons in Them these lone pairs creates lonepair-lone pair repulsion between $F-F,N-N$ and $O-O$ molecules. Due to which it will increase its bond length and decrease the bond energy. so, The correct option is $C-C$ as there are no lone pairs present on carson atom
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$(A)$ $(a)$ $n=3,1=1, m_{l}=1, m_{s}=+\frac{1}{2}$
$\quad (b)$ $n =3,1=2, m _{l}=1, m _{s}=+\frac{1}{2}$
$(B)$ $(a)$ $n =3,1=2, m _{l}=-2, m _{s}=-\frac{1}{2}$
$\quad (b)$ $n =3,1=2, m _{l}=-1, m _{s}=-\frac{1}{2}$
$(C)$ $(a)$ $n=4,1=2, m_{l}=2, m_{s}=+\frac{1}{2}$
$\quad (b)$ $n =3,1=2, m _{l}=2, m _{s}=+\frac{1}{2}$
The pairs of electron present in degenerate orbitals is/are...... .
