$4 \times 10^{-5}-y=10^{-5}$
$y=3 \times 10^{-5}$
$(x-y)\left(4 \times 10^{-5}-y\right)=10^{-10}$
$(x-y)\left(10^{-3}\right)=10^{-10}$
$x-y=10^{-5}$
$x-3 \times 10^{-5}=10^{-5}$
$x=4 \times 10^{-5}$
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$(I)\, H_2S_2O_6$ $(II)\, H_2S_2O_3$ $(III)\,H_2S_2O_5$
$\mathrm{X} \rightleftharpoons \mathrm{Y} ; \mathrm{K}_1=1.0$
$\mathrm{Y} \rightleftharpoons \mathrm{Z} ; \mathrm{K}_2=2.0$
$\mathrm{Z} \rightleftharpoons \mathrm{W} ; \mathrm{K}_3=4.0$
The equilibrium constant for the reaction $\mathrm{X} \rightleftharpoons \mathrm{W}$ is
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C{H_2} - C = C - CH - C - C{H_2} - C{H_2} - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,}\\
{{C_2}{H_5}}
\end{array}$
