MCQ
The moment of inertia of a disc of mass $M$ and radius $R$ about a tangent to its rim in its plane is
- ✓$ \frac{5}{4}M{R^2} $
- B$ \frac{2}{3}M{R^2} $
- C$ \frac{3}{2}M{R^2} $
- D$ \frac{4}{5}M{R^2} $
✓
Answer
Correct option: A.
$ \frac{5}{4}M{R^2} $
a
The moment of inertia of a disc about its diameter is $I_{0}=\frac{M R^{2}}{4}$
The moment of inertia of a disc about its diameter is $I_{0}=\frac{M R^{2}}{4}$
According to parallel axis theorem, moment of inertia about the required axis is
$I=I_{0}+M d^{2}$
$I=\frac{M R^{2}}{4}+M R^{2}=\frac{5 M R^{2}}{4}$
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