MCQ
The most probable radius (in pm) for finding the electron in $H{e^ + }$ is
- A$0.0$
- B$52.9$
- ✓$26.5$
- D$105.8$
where $a_0 = 52.9\, pm. $ For helium ion, $Z = 2.$
$rmp = $ $\frac{{52.9}}{2}$ $= 26.45\, pm.$
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$Mn^{2+} +2e- \rightarrow Mn;\, E^o = -1.18\,V$
$2(Mn^{3+} +e^- \rightarrow Mn^{2+} )\,;\,E^o=+1.51\,V$
The $E^o$ for $3Mn^{2+} \rightarrow Mn+ 2Mn^{3+}$ will be :
$(i)$ A $0.5\,m$ $NaBr$ solution has a higher vapour pressure than a $0.5\,m\,BaCl_2$ solution at the same temperature
$(ii)$ Pure water freezes at the higher temperature than pure methanol
$(iii)$ a $0.1\,m\,NaOH$ solution freezes at a lower temperature than pure water
Choose the correct answer from the codes given below
$2N{H_3}(g)\xrightarrow[{Pt\,catalyst}]{{1130\,K}}{N_2}(g) + 3{H_2}(g)$
Choose the option which is not true with respect to the reaction, from the choices given below :-
Statement $-I :$ The pentavalent oxide of group$- 15$ element. $E _{2} O _{5}$. is less acidic than trivalent oxide. $E _{2} O _{3}$. of the same element.
Statement $-II :$ The acidic character of trivalent oxide of group $15$ elements. $E _{2} O _{3}$. decreases down the group.
In light of the above statements. choose most appropriate answer from the options given below