MCQ
The most probable radius (in pm) for finding the electron in $H{e^ + }$ is
- A$0.0$
- B$52.9$
- ✓$26.5$
- D$105.8$
where $a_0 = 52.9\, pm. $ For helium ion, $Z = 2.$
$rmp = $ $\frac{{52.9}}{2}$ $= 26.45\, pm.$
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$\mathrm{C}_{2} \mathrm{H}_{7} \mathrm{~N}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{CuO} \rightarrow \mathrm{x\,CO}_{2}+\frac{y}{2} \mathrm{H}_{2} \mathrm{O}+\frac{\mathrm{z}}{2} \mathrm{~N}_{2}+\left(2\, \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{Cu}$
The value of $y$ is ...... .(Integer answer)
$(a)$ Polarising power of cation
$(b)$ Extent of distortion of anion
$(c)$ Polarisability of the anion
$(d)$ Polarising power of anion
$\begin{array}{*{20}{c}}
{C{H_3}C{H_2} - N - C{H_2}C{H_3}} \\
{|\,} \\
{C{H_3}}
\end{array}$
is :