MCQ
The multiplicative inverse of $7^{-2}$is:
- A$7$
- ✓$7^2$
- C$\frac{1}{7^2}$
- D$\frac{1}{7}$
✓
Answer
Correct option: B.
$7^2$
B. $7^2$
Solution:
The multiplicative inverse of any value is the one which when multiplied by the original value gives a value equal to $1.$
$7^{-2} = \frac{1}{7^2}$
Hence, $7^{-2}\times\frac{1}{7^2} = 1$
Solution:
The multiplicative inverse of any value is the one which when multiplied by the original value gives a value equal to $1.$
$7^{-2} = \frac{1}{7^2}$
Hence, $7^{-2}\times\frac{1}{7^2} = 1$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
What is the one’s digit in the cube root of the cube number $3375$?
→If $x^{2}-x-42=(x+k)(x+6),$ then $k=$
→Read the graph and answer the related questions:
$500$ books are of which subject?
→$500$ books are of which subject?
If a number of n-digits is a perfect square and $‘n’$ is an even number, then which of the following is the number of digits of its square root?
→$(a+1)(a-1)\left(a^2+1\right)=?$
→What is the value of the expression $2ab + 3bc + 4ac$, when $a = b = c = 1?$
→Solve, $5t - 3 = 3t - 5$
→What is the sum of the additive inverse and multiplicative inverse of $2?$
→$(0.8)^3=?$
→Multiplicative inverse of a negative rational number is