MCQ
The normality of $10\,lit.$ volume hydrogen peroxide is
- A$0.176$
- B$3.52$
- ✓$1.78$
- D$0.88$
✓
Answer
Correct option: C.
$1.78$
c
(c) ${H_2}{O_2} \to {H_2}O + \frac{1}{2}{O_2}$
(c) ${H_2}{O_2} \to {H_2}O + \frac{1}{2}{O_2}$
$1 M$ ${H_2}{O_2}$solution $ = 2N = 34\,gm/litre = 11.2$
So Normality $ = \frac{{2 \times 10}}{{11.2}} = 1.78$
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