MCQ
The normality of $4\%$ $(w/V)$ $NaOH$ is
- A$0.1$
- ✓$1$
- C$0.05$
- D$0.01$
✓
Answer
Correct option: B.
$1$
b
$N = \frac{{4 \times 1000}}{{40 \times 100}} = 1.0$
$N = \frac{{4 \times 1000}}{{40 \times 100}} = 1.0$
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