MCQ
The normality of $H _{2} SO _{4}$ in the solution obtained on mixing $100 mL$ of $0.1\,M H _{2} SO _{4}$ with $50 mL$ of $0.1$ $M\,NaOH$ is $\times 10^{-1}\,N$. (Nearest Integer)
- ✓$1$
- B$2$
- C$3$
- D$4$
No. of equivalents of $NaOH =50 \times 0.1=5$
No. of equivalents of $H _{2} SO _{4}$ left $=20-5=15$
$150 \times x =15$
$x =\frac{1}{10}=0.1 N =1 \times 10^{-1}\,N$
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