The number _ 20 3 lies in - Vidyadip

MCQ

The number ${\log _{20}}3$ lies in

A
$\left( {1/4,\,\,1/3} \right)$
✓
$\left( {1/3,\,\,1/2} \right)$
C
$\left( {1/2,\,3/4} \right)$
D
$\left( {3/4,\,\,4/5} \right)$

✓

Answer

Correct option: B.

$\left( {1/3,\,\,1/2} \right)$

b
(b) ${20^{1/3}} < 3 < {20^{1/2}}$$ \Rightarrow $${1 \over 3} < {\log _{20}}3 < {1 \over 2}$

$\therefore {\log _{20}}3 \in \left( {{1 \over 3},\,{1 \over 2}} \right)$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

If $\overrightarrow{ x }$ and $\overrightarrow{ y }$ be two non$-$zero vectors such that $|\overrightarrow{ x }+\overrightarrow{ y }|=|\overrightarrow{ x }|$ and $2 \overrightarrow{ x }+\lambda \overrightarrow{ y }$ is perpendicular to $\overrightarrow{ y },$ then the value of $\lambda$ is

$\mathop {\lim }\limits_{x \to 0} \,x^2(1+2+3+...+[\frac{1}{|x|}])$ is equal to

(where [.] denotes greatest integer function)

The integral $\int \frac{(2 x-1) \cos \sqrt{(2 x-1)^{2}+5}}{\sqrt{4 x^{2}-4 x+6}} d x$ is equal to (where $c$ is a constant of integration)

The mean of $5$ numbers is $18$. If one number is excluded, their mean becomes $16$. Then the excluded number is

The length of the perpendicular from point $(1, 2, 3)$ to the line $\frac{{x - 6}}{3} = \frac{{y - 7}}{2} = \frac{{z - 7}}{{ - 2}}$ is

If in the expansion of ${(1 + x)^m}{(1 - x)^n}$, the coefficient of $x$ and ${x^2}$ are $3$ and $-6$ respectively, then m is

For $x \in(0, \pi)$, the equation $\sin x+2 \sin 2 x-\sin 3 x=3$ has

A card is drawn at random from a pack of $52$ cards. The probability that the drawn card is a court card i.e. a jack, a queen or a king, is

The value of the expression
$3(1!) - 4(2!) + 5(3!) - 6(4!) ...... - 2008(2006)!+ (2007)!$ is

Let $n \geq 3$. A list of numbers $0 < x_1 < x_2 < \ldots < x_n$ has mean $\mu$ and standard deviation $\sigma$. A new list of numbers is made as follows: $y_1=0, y_2=x_2, \ldots, x_{n-1}$ $=x_n-1, y_n=x_1+x_n$. The mean and the standard deviation of the new list are $\hat{\mu}$ and $\hat{\sigma}$. Which of the following is necessarily true?