The number of dry cells, each of $e.m.f.$ $1.5\,volt$ and internal resistance $0.5\, ohm$ that must be joined in series with a resistance of $20\, ohm$ so as to send a current of $0.6\,A$ through the circuit is
A$2$
B$8$
C$10$
D$12$
Medium
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C$10$
c In series $i = \frac{{nE}}{{nr + R}}$ $ \Rightarrow $ $0.6 = \frac{{n \times 1.5}}{{n \times 0.5 \times 20}}$ $ \Rightarrow $ $n = 10$
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The number density of free electrons in copper is nearly $8 \times 10^{28}\,m ^{-3} . A$ copper wire has its area of cross section $=2 \times 10^{-6}\,m ^2$ and is carrying a current of $3.2\,A$. The drift speed of the electrons is $.....\times 10^{-6}\,ms ^{-1}$.
$n$ identical cells each of $e.m.f.$ $E$ and internal resistance $r$ are connected in series. An external resistance $R$ is connected in series to this combination. The current through $R$ is