MCQ
The number of five-digit telephone numbers having at least one of their digits repeated is:
  • A
    90000.
  • B
    100000.
  • C
    30240.
  • 69760

Answer

Correct option: D.
69760
Total number of five digit numbers (since there is no restriction of the number 0XXXX) = 10 × 10 × 10 × 10 × 10 = 100000.
These numbers also include the numbers where the digits are not being repeated. So, we need to subtract all such numbers.
Number of 5 digit numbers that can be formed without any repetition of digits = 10 × 9 × 8 × 7 × 6 = 30240
$\therefore$ Number of five-digit telephone numbers having at least one of their digits repeated = {Total number of 5 digit numbers} - {Number of numbers that do not have any digit repeated} = 100000 - 30240 = 69760

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

For a frequency distribution mean deviation from mean is computed by:
If $\frac{{{{\cos }^4}\,\alpha }}{{{{\cos }^2}\,\beta }}\, + \,\frac{{{{\sin }^4}\,\alpha }}{{{{\sin }^2}\,\beta }}\, = \,1$ , then the value of $\left[ {\frac{{{{\cos }^4}\,\beta }}{{{{\cos }^2}\,\alpha }}\, + \,\frac{{{{\sin }^4}\,\beta }}{{{{\sin }^2}\,\alpha }}\,} \right]$ is (where $[.]$ denotes greatest integer function)
The coefficient of $x ^7$ in $\left(1-x+2 x^3\right)^{10}$ is $........$.
Let $\mathrm{x}_1, \mathrm{x}_2, \ldots, \mathrm{x}_{\mathrm{n}}$ be n observations. Let $\mathrm{y}_{\mathrm{i}}=\mathrm{a} \mathrm{x}_{\mathrm{i}}+\mathrm{b} \mathrm{y}_{\mathrm{i}}+\mathrm{b}$ for $\mathrm{i}=1,2,3, \ldots, \mathrm{n}$, where a and b are constants. If the mean of $x_i^{\prime} s$ is 48 and their standard deviation is 12 , the mean of $y_i$ 's 55 and standard deviation of $y_i$ 's is 15 , the values of a and b are:
The tangent and the normal lines at the point $(\sqrt 3,1)$ to the circle $x^2 + y^2 = 4$ and the $x -$ axis form a triangle. The area of this triangle (in square units) is
Let $P$ be an interior point of a convex quadrilateral $A B C D$ and $K, L, M, N$ be the mid-points of $A B, B C$, $C D, D A$ respectively. If Area $(P K A N)=25$, Area $(P L B K)=36$, and Area $(P M D N)=41$ then Area $(P L C M)$ is
The range of the function f(x) = |x - 1| is:
If ${^\text{15}}\text{C}_{3\text{r}}={^\text{15}}\text{C}_{\text{r+3}},$ is then equal to:
A line $L$ passes through the points $(1, 1)$ and $(2, 0)$ and another line $L'$ passes through $\left( {\frac{1}{2},0} \right)$ and perpendicular to $L$. Then the area of the triangle formed by the lines $L,L'$ and $y$- axis, is
The number of solution of the equation $\tan x + \sec x = 2\cos x$ lying in the interval $(0,2\pi )$ is