MCQ
The number of hydroxyl group$(s)$ in $Q$ is


- A$1$
- B$2$
- C$3$
- ✓$4$


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takes places through the mechanism given below :
$NO + Br _2 \Leftrightarrow NOBr _2 \text { (fast) }$
$NOBr _2+ NO \rightarrow 2 NOBr \text { (slow) }$
The overall order of the reaction is $.....$.
$2X_2(s) + 3Y^{2+} (aq) \to 2X_2^{3+}(aq) + 3Y(s)$