MCQ
The number of isomers possible for square planar complex ${K_2}\left[ {PdClB{r_2}(SCN)} \right]$ is
- A$2$
- B$3$
- ✓$4$
- D$6$
✓
Answer
Correct option: C.
$4$
c
(c) Geometrical isomers (cis and trans) and linkage isomers ($-SCN$ and $ -NCS$).
(c) Geometrical isomers (cis and trans) and linkage isomers ($-SCN$ and $ -NCS$).
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