MCQ
The number of nine digit numbers that can be formed with different digits is:
  • A
    9.8!
  • B
    8.9!
  • C
    9.9!
  • D
    10!

Answer

  1. 9.9!

Solution:

The first digit is one of (1, 2, 3, 4, 5, 6, 7, 8, 9) (i.e., all expect 0).

So, the no of ways $=9$

The remaining 8 digits are to be taken from the remaining 9 numbers.

So, the no of ways $= \ ^9\text{P}_8$

So, total no. of ways $=9\times\ ^9\text{P}_8$

$=9\times9!$

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