MCQ
The number of orbitals in $2p$ sub-shell is
- A$6$
- B$2$
- ✓$3$
- D$4$
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$\begin{array}{*{20}{c}}
{C{H_3}}\\
{|\,\,\,\,\,}\\
{{C_6}{H_5}C{H_2} - C - C{H_2} - C{H_3}}\\
{|\,\,\,\,\,}\\
{Br\,\,\,}
\end{array}$ $\xrightarrow[{{C_2}{H_5}OH}]{{{C_2}{H_5}ONa}}$
Which conformer of above compound is most stable across $C_2 - C_3$ ?

$C{H_3}CN\xrightarrow{{Na/{C_2}{H_5}OH}}A\xrightarrow{{HN{O_2}}}B\xrightarrow{{{\text{copper}}}}C$