MCQ
The number of orbitals in the fourth principal quantum number will be
- A$4$
- B$8$
- C$12$
- ✓$16$
$ \Rightarrow {4^2} = 16$
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$20 \;g \;\;\;\;5 \;g$
Consider the above reaction, the limiting reagent of the reaction and number of moles of $NH _{3}$ formed respectively are
$(a)$ Electron density in the $XY$ plane in $3d_x^2 - 3d_y^2$ orbital is zero
$(b)$ Electron density in the $XY$ plane in $3d_z^2$ orbital is zero
$(c)$ $2s$ orbital has one nodal surface
$(d)$ For $2pz$ orbital $YZ$ is the nodal plane.
Specify True or False.
The total number of methyl $\left(- CH _3\right)$ group($s$) in compound $S$ is. . . .