MCQ
The number of unpaired electrons in a chromic ion $C{r^{3 + }}$ (atomic number $= 24$) is
- A$6$
- B$4$
- ✓$3$
- D$1$
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${N_2}(g)\, + \,{O_2}(g)\,\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}\,2NO(g)$
$C_0=Ce^{-2.1 \times 10^{-3}t}$ for the forward reaction and $C'_0=C'e^{-4.2 \times 10^{-4}t}$ for the backward reaction, hence $K_c$ for the above equilibrium is :-