MCQ
The number of unpaired electrons in $F{e^{3 + }}(Z = 26)$ are
- ✓$5$
- B$6$
- C$3$
- D$4$
✓
Answer
Correct option: A.
$5$
a
(a) $F{e^{3 + }}$$(z = 26)$
(a) $F{e^{3 + }}$$(z = 26)$
$F{e^{3 + }} = [Ar]\,3{d^5}4{s^0}$
Total no. of unpaired electron $=5$
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