MCQ
The number of unpaired electrons in the $F{e^{2 + }}$ ion is
- A$0$
- ✓$4$
- C$6$
- D$3$
$Fe_{26}^{2 + } = [Ar]\,3{d^6},4{s^0}$
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Here $X, Y$ are respectively
$A. \;n =3, l=2, m _{1}=1, m _{ s }=+1 / 2$
$B.\; n =4, l=1, m _{1}=0, m _{ s }=+1 / 2$
$C. \;n =4, l=2, m _{1}=-2, m _{ s }=-1 / 2$
$D. \;n =3, l=1, m _{1}=-1, m _{ s }=+1 / 2$
The correct order of increasing energy is
