MCQ
The number of water molecules is maximum in
- A$1.8\ gram$ of water
- B$18\ gram$ of water
- ✓$18\ moles$ of water
- D$18$ molecules of water.
$\ln 18 \;\mathrm{g}=1 \mathrm{moles}$
$1\; mole$ contain $6.022 \times 10^{23}$ molecules of water
so $18\; moles$ contain maximum number of molecules
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$6CO_2 + 6H_2O + solar energy \to C_6H_{12}O_6+6O_2$
A blue whales gain $75\ kg$ of mass per day by feeding on krill. The whale must consume ten times this mass of krill each day. The krill must consume $10.0\ kg$ of diatoms to produce $1.0\ kg$ of krill. Assuming that the mass gain of a whale's life is due to the consumption of carbohydrates $(C_6H_{12}O_6)$ , calculate the moles of $CO_2$ that must be used by the diatoms to produce the carbohydrates consumed by a blue whale in a day
$XeO _{3}, XeO _{2} F _{2}, XeO _{4}, XeO _{3} F _{2}, Ba _{2} XeF _{4}$