Question
The number which exceeds its square by the greatest possible quantity is,
- $\frac{1}{2}$
- $\frac{1}{4}$
- $\frac{3}{4}$
- None of these.
Solution:
Let the required number be x.
Then, f'(x) = x - x2
lmplies that f(x) = 1 - 2x = 0
For a local maxima or a local minima, we must have f'(x) = 0
lmplies that 2x = 1
lmplies that $\text{x}=\frac{1}{2}$
Now, f''(x) = -2 < 0
Therefore, $\text{x}=\frac{1}{2}$ is a local maxima.
Hence, the required number is $\frac{1}{2}$.
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