Question
The obtuse angle between the lines $y = - \;2$ and $y = x + 2$ is ....$^o$

Answer

b
(b) The gradient of the line $y = x + 2$ is $1$. Therefore, it makes an angle of ${45^o}$ with $x$-axis. The second line is parallel to $x$-axis. Hence the obtuse angle between the lines is ${135^o}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The area of the region bounded by $y=|| x-3|-4|-5$ and the $X$-axis is
$i\,.\,(j \times k) + j\,.\,(k \times i) + k\,.\,(i \times j) = $
Let for any three distinct consecutive terms $a, b, c$ of an $A.P,$ the lines $ax + by + c =0$ be concurrent at the point $P$ and $Q(\alpha, \beta)$ be a point such that the system of equations $x+y+z=6$
$2 x+5 y+\alpha z=\beta$ and $x+2 y+3 z=4$, has infinitely many solutions. Then $(P Q)^2$ is equal to $............ .$
The number of common tangents to the circles ${x^2} + {y^2} - 4x - 6y - 12 = 0$ and ${x^2} + {y^2} + 6x + 18y + 26 = 0$ is
The sum of the series

$\frac{1}{{1 + \sqrt 2 }} + \frac{1}{{\sqrt 2  + \sqrt 3 }} + \frac{1}{{\sqrt 3  + \sqrt 4 }} + .....$ upto $15$ terms is

Let $a_1 , a_2, a_3, .... , a_n,$ be in $A.P$. If $a_3 + a_7 + a_{11} + a_{15} = 72$ , then the sum of its first $17$ terms is equal to
If $f$ is a differentiable function such that $f(2x + 1) = f(1 -2x)$ $\forall \,\,x \in R$ then minimum number of roots of the equation $f'(x) = 0$ in $x \in \left( { - 5,10} \right)$ ,given that $f(2) = f(5) = f(10)$ , is
The expression $2\cos \frac{\pi }{{13}}.\cos \frac{{9\pi }}{{13}} + \cos \frac{{3\pi }}{{13}} + \cos \frac{{5\pi }}{{13}}$ is equal to
The value of the integral $\int_{0}^{\pi}|\sin 2 x| dx$ is
$l,m,n$ are the ${p^{th}},{q^{th}}$and ${r^{th}}$term of a G.P., all positive, then $\left| {\,\begin{array}{*{20}{c}}{\log l}&{p\,\,\,\,\,\begin{array}{*{20}{c}}1\end{array}}\\{\log m}&{q\,\,\,\,\,\begin{array}{*{20}{c}}1\end{array}}\\{\log n}&{r\,\,\,\,\,\begin{array}{*{20}{c}}1\end{array}}\end{array}\,} \right|$ equals