- ATwo free ions
- BTwo-carbanium ion
- CTwo carbanion
- ✓A cation and an anion
$Cl$ is more electronegative than $C$ by which it form anion and hydrocarbon form cation.
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$(a)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - Br} \\
{|\,\,} \\
{\,\,\,\,\,{C_2}{H_5}\,}
\end{array}$ $(b)$ $\begin{array}{*{20}{c}}
{\,\,Br\,} \\
{|\,} \\
{C{H_3} - C - C{H_3}} \\
{|\,} \\
{\,\,\,\,\,{C_2}{H_5}}
\end{array}$ $(c)$ $\begin{array}{*{20}{c}}
{{C_2}{H_5} - CH - C{H_2}Br} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,} \\
{{C_2}{H_5}\,\,}
\end{array}$
$M\left( s \right) + 2{H^ + }\left( {1M} \right) \to {H_2}\left( {1atm} \right) + {M^{2 + }}\left( {0.1M} \right)$
is $1.5\,V$. The standard reduction potential for $M^{2+}/M(s)$ couple is ............. $\mathrm{V}$
