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Wave Optics — Physics STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsWave Optics3 Marks
Question
The optical path difference between identical waves from two coherent sources and arriving at a point is 172 . What can you say about the resultant intensity at the point? If the path difference is $9.18 \mu m$, calculate the wavelength of light.
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Answer

Data: Path difference $=17 \lambda=9.18 \mu m$
(i) Path difference $=17 \lambda=n \lambda$, where $n=17$
As the path difference is an integral multiple of the wavelength $\lambda$ the point where the waves interfere is a bright point with maximum intensity.
(ii) $17 \lambda=9.18 \mu m =9.18 \times 10^6 m$
$
\therefore \lambda=\frac{9.18 \times 10^{-6}}{17}=5.4 \times 10^{-7} m =5400 Å
$

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