MCQ
The orbital angular momentum of $3p$ electron is
  • A
    $\sqrt 3\ h$
  • B
    $\sqrt 6\ h$
  • C
    zero
  • $\sqrt 2 \frac{h}{{2\pi }}$

Answer

Correct option: D.
$\sqrt 2 \frac{h}{{2\pi }}$
d
Orbital angular momentum $ = \sqrt {l(l + 1)} \frac{h}{{2\pi }}$ $l=1$ for $\mathrm{p}-$ orbital.

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