MCQ
The orbital angular momentum of an electron in $s$ orbital is
- A$ + \frac{1}{2}.\frac{h}{{2\pi }}$
- ✓Zero
- C$\frac{h}{{2\pi }}$
- D$\sqrt 2 .\frac{h}{{2\pi }}$
Angular momentum $ = \sqrt {l(l + 1)} \frac{h}{{2\pi }} = 0$.
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[Given : $h =6.63 \times 10^{-34}\, J \,s$, and $c =3 \times 10^{8} \,m\, s ^{-1}$ ]