MCQ
The outer electronic configuration of radioactive element present in IA group is:
- A8s1
- B7s1
- C5s1
- D6s1
Explanation:
The radioactive element in group 1A is francium (Fr) atomic number 87 having electronic configuration (Rn) 7s1.
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$\begin{matrix}
O \\
|| \\
H-C-H, \\
\end{matrix}\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,O\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,||\,\,\,\,\, \\
H-C-C{{H}_{2}}-C-C-C{{H}_{3}}, \\
\end{matrix}\begin{matrix}
\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
C{{H}_{3}}-C-C{{H}_{2}}-C-H \\
\end{matrix}$
aalkene $(A)$ will be ?
$C{H_4}(g) + 2{O_2}(g) \to C{O_2}(g) + 2{H_2}O(l)$ ;
${\Delta _r}{H_{300}} = - 212.7\ Kcal / mol$ .
The absolute value of ${\Delta _r}U_{300}^o$ for this reaction is .......$Kcal\,/\,mol$ $(R = 2\ cal/mol-K)$