

$Gate-I$ is AND gate, $gate-II$ is $NANO$ gate.
Output $\quad Y=\overline{(A . B . C)}$
when $A=1, B=1, C=1,$ then
$Y=\overline{(1.1) .1}=\overline{1.1}=\overline{1}=0$
when $\quad A=0, B=0, C=0,$ then
$Y=\overline{(0.0) .0}=\overline{0.0}=\overline{0}=1$
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$V\left( {x,y,z} \right) = \left\{ {\begin{array}{*{20}{c}}
{0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,for\,x\, < \, - d}\\
{ - {V_0}{{\left( {1 + \frac{x}{d}} \right)}^2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,for\, - \,d\, \le x < 0}\\
{ - {V_0}\left( {1 + 2\frac{x}{d}} \right)\,\,\,\,\,\,\,\,\,\,\,for\,0\, \le x < d}\\
{ - 3{V_0}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,for\,x\, > \,d}
\end{array}} \right.$
where $-V_0$ is the potential at the origin and $d$ is a distance. Graph of electric field as a function of position is given as
Reason $(R):$ Here we cannot apply conservation of linear momentum.