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STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium) — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)4 Marks
MCQ
The overall complex dissociation equilibrium constant for the complex $[Cu(NH_3)_4]^{2+}$ ion will be ( $\beta _4$ for this complex is $2.1\times 10^{13}$ ) $\beta _4 =$ association constant
  • ✓
    $4.7\times 10^{-14}$
  • B
    $2.1\times 10^{13}$
  • C
    $11.9\times 10^{-2}$
  • D
    $2.1\times 10^{-13}$
✓

Answer

Correct option: A.
$4.7\times 10^{-14}$
a
$\mathrm{K}=\frac{1}{\beta_{4}} $

$=\frac{1}{2.1 \times 10^{13}} $

$=4.7 \times 10^{-14}$

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