MCQ
The oxidation number of cobalt in $K[Co{(CO)_4}]$ is
- A$1$
- ✓$-1$
- C$3$
- D$-3$
✓
Answer
Correct option: B.
$-1$
b
(b) $1 \times ( + 1) + x + 4 \times (0) = 0$
(b) $1 \times ( + 1) + x + 4 \times (0) = 0$
$1 + x = 0 \Rightarrow x = - 1$ Oxidation number of Co $ = - 1$.
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