MCQ
The oxidation number of cobalt in $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_4\right]$ is:
- A$+1$
- B$+3$
- ✓$–1$
- D$–3$
✓
Answer
Correct option: C.
$–1$
We know that $CO$ is a neutral ligand and $K$ carries a charge of $+1.$ Therefore, the complex can be written as $\mathrm{K}^{+}\left[\mathrm{Co}(\mathrm{CO})_4\right]^{-} .$ Therefore, the oxidation number $−$ of $Co$ in the given complex is $-1.$ Hence, option $(iii)$ is correct.
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