Question
The oxidation number of nitrogen in $NO_3^ - $ is
$x - 2 \times 3 = - 1$; $x = 6 - 1 = + 5$.
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[nearest integer]
(Given: atomic mass of $N =14\, g \,mol ^{-1}$ and of $O$ $=16\, g\, mol ^{-1}$.
Molar heat capacity of $N _{2} O$ is $100\, JK ^{-1}\, mol ^{-1}$ )