The oxidation number of Pt in [Pt( C_2 H_4 )C l_3 ]^ - is - Vidyadip

MCQ

The oxidation number of $ Pt$ in ${[Pt({C_2}{H_4})C{l_3}]^ - }$ is

A
$ + 1$
✓
$ + 2$
C
$ + 3$
D
$ + 4$

✓

Answer

Correct option: B.

$ + 2$

b
Let $x$ be the oxidation state of $Pt$ in $\left[ Pt \left( C _2 H _4\right) Cl _3\right]^{-}$.

Since the overall charge on the complex is $-1$, the sum of oxidation states of all elements in it should be equal to $-1$.

Therefore, $x +0-3=-1$

or, $x =+2$

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