MCQ
The oxidation number of $Pt$ in ${[Pt({C_2}{H_4})\,C{l_3}]^ - }$ is
- A$+1$
- ✓$+2$
- C$+3$
- D$+4$
✓
Answer
Correct option: B.
$+2$
b
(b)In complex ${[Pt({C_2}{H_4})C{l_3}]^ - }$ $Pt$ have $+ 2$ oxidation state.
(b)In complex ${[Pt({C_2}{H_4})C{l_3}]^ - }$ $Pt$ have $+ 2$ oxidation state.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
An organic compound $[A],$ molecular formula $C _{10} H _{20} O _{2}$ was hydrolyzed with dilute sulphuric acid to give a carboxylic acid $[ B ]$ and alcohol $[C].$ Oxidation of $[C]$ with CrO $_{3}- H _{2} SO _{4}$ produced $[B].$ Which of the following structures are not possible for $[ A ] ?$
→The least reactive chlorine is present in:
When $KHSO_4$ is added into a concentrated solution of $H_2SO_4$, the acidity of the solution
→Which of the following has maximum volatility
At ${25\,^o}C$ Ethylene glycol is a
→$IUPAC$ name of $H_2 [PtCl_6]$ is
→$STATEMENT-1$: $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4$ is paramagnetic. and
→$STATEMENT-2$: The $\mathrm{Fe}$ in $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}_3 \mathrm{SO}_4\right.$ has three unpaired electrons.
Pressure cooker reduces cooking time for food because
Which of the following $0.10\,m$ aqueous solution will have the lowest freezing point
→${image}$
→In the above reaction, $3.9\, g$ of benzene on nitration gives $4.92\, g$ of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is............. $\%$. (Round off to the Nearest Integer).
(Given atomic mass: $C : 12.0\, u , H : 1.0\, u$$O : 16.0\, u , N : 14.0\, u )$