MCQ
The oxidation number of sulphur in ${H_2}S{O_4}$ is
- A$-2$
- B$+2$
- C$+4$
- ✓$+6$
$2 + x - 2 \times 4 = 0$, $x = 8 - 2 = + 6$.
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Given : Atomic masses of $C , H$ and $N$ are $12,1$ and $14\, amu$ respectively.
The molar mass of the compound $A$ is $162\, g\, mol ^{-1}$.
