MCQ
The oxidation state of $Cr$ in $C{r_2}O_7^{2 - }$ is
- A$4$
- B$-6$
- ✓$6$
- D$-2$
✓
Answer
Correct option: C.
$6$
(c) $\mathop {C{r_2}O_7^{2 - }}\limits^{ * \,\,\,\,\,\,\,\,\,\,\,\,\,} $
$2x - 2 \times 7 = - 2$; $2x = 14 - 2 = 12$
$x = \frac{{12}}{2} = + 6$.
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