MCQ
The oxidation state of $Fe$ in ${K_4}[Fe{(CN)_6}]$ is
  • $2$
  • B
    $-2$
  • C
    $3$
  • D
    $4$

Answer

Correct option: A.
$2$
a
(a) $4 \times ( + 1) + x + 6 \times - 1 = 0$

or $x = + 6 - 4 = + 2$

Oxidation state of $Fe = + 2$

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