MCQ
The oxidation state of $N$ in $HNO _{4}$ is
- A$+7$
- ✓$+5$
- C$-3$
- D$+3$
✓
Answer
Correct option: B.
$+5$
b
$HNO _{2} O _{2}$ (one Peroxybond)
$HNO _{2} O _{2}$ (one Peroxybond)
$+1+N+2(-2)+2(-1)=0$
$N=+5$
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