- ✓$Cu ^{+}, Zn ^{2+}$
- B$Cu ^{2+}, Zn ^{2+}$
- C$V ^{3+}, Cr ^{3+}$
- D$Mn ^{3+}, Fe ^{3+}$
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$(A)$ $CH_3CH_2-CH_2-OH$ $ (B) $ $\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - OH} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(C)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - C{H_2} - C - OH} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$CH_3CH_2CH_2Br + NaCN \to $$CH_3CH_2CH_2CN+ NaBr$
This reaction will be the fastest in
take place in two steps :
$(a)$ $Br^{-} + H^{+} + H_2O_2 \xrightarrow{{slow}} HOBr + H_2O$
$(b)$ $HOBr + Br^{-} + H^{+} \xrightarrow{{fast}} H_2O + Br_2$
The order of the reaction is
$Image$
$1.$ The structure of the product $\mathrm{I}$ is
A,B,C,D, $Image$
$2.$ The structures of compounds $J$ and $K$ respectively are
A,B,C,D, $Image$
$3.$ The structure of product $L$ is
A,B,C,D, $Image$
Give the answer question $1,2$ and $3.$
$t/s$ $0$ $30$ $60$ $90$
$Ester/mol\, L^{-1}$ $0.55$ $0.31$ $0.17$ $0.085$
What will be the average rate of reaction between the time interval $30$ to $60$ seconds?