- A$SO_2, CO_2$
- ✓$CO_2, Br_3^-$
- C$PCl_5, I_3^-$
- D$CH_4, COCl_2$
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$A \rightarrow B; \ \ \ K_1 = 10^{15}\ exp.\ \left( {\frac{{ - 2000}}{T}} \right)$
$C \rightarrow D;\ \ \ K_2 = 10^{14}\ exp. \ \left( {\frac{{ - 1000}}{T}} \right)$
The temperature at which $K_1 = K_2$ is ........... $K$ ($exp. = e$)
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,C{H_3}}\\
{\,\,\,|\,\,}\\
{C{H_3} - C{H_2} - CH - C - N{H_2}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,}
\end{array}$ $\xrightarrow[\Delta ]{{B{r_2}/KOH}}\left( A \right)\xrightarrow{\begin{subarray}{l}
(1)\,\,C{H_3}I\,{\text{(excess)}} \\
(2)\,AgOH/\Delta \,
\end{subarray} }$ $(B)$


$(A)$ $CO _2, C _2 H _4, NO$ and $HCl$
$(B)$ $NO _2, O _3, HCl$ and $H _2 SO _4$
$(C)$ $BCl _3, NO , NO _2$ and $H _2 SO _4$
$(D)$ $CO _2, BCl _3, O _3$ and $C _2 H _4$
Reason : $NH_3$ is non-polar.