Download App

3. Classification of elements and periodicity in properties — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry3. Classification of elements and periodicity in properties1 Mark
MCQ
The pair that has similar atomic radii is
  • A
    $Ti$ and $Hf$
  • B
    $Mn$ and $Re$
  • C
    $Sc$ and $Ni$
  • ✓
    $Mo$ and $W$
✓

Answer

Correct option: D.
$Mo$ and $W$
d
Due to lanthanoide contraction $Mo$ and $W$ have similar atomic radii.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 3. Classification of elements and periodicity in properties→3. Classification of elements and periodicity in properties — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

When two mole of an ideal gas $\left( {{C_{p.m.}} = \frac{5}{2}\,R} \right)$ heated from $300\, K$ to $600\, K$ at constant pressure. the change in entropy of gas $\left( {\Delta S} \right)$ is
→
The ratio of two of the first four Bohr’s orbits of the hydrogen atom are in the ratio $1 : 4$ The energy difference between them may be 
→
A sample of $\mathrm{CaCO}_3$ and $\mathrm{MgCO}_3$ weighed $2.21 \mathrm{~g}$ is ignited to constant weight of $1.152 \mathrm{~g}$. The composition of mix ture is :

(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1}{CaCO}_3: 100, \mathrm{MgCO}_3: 84)$

→
Which of the following will have least hindered rotation about carbon-carbon bond
→
Which of the following compounds represents acrylonitrile
→
Aromatic properties of benzene are proved by
→
Correct IUPAC name for $\text{H}_3\text{C}-\text{CH}-\text{CH}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{C}_2\text{H}_5\ \text{C}_2\text{H}_5$ ___________.
→
Assertion :Fluorine molecule has bond order one.
Reason : The number of electrons in the antibonding molecular orbitals is two less than that in bonding molecular orbitals.
→
$CH_2=CH-CH_2-CH_3 \xrightarrow{{{H^ \oplus }/\Delta }} Major \,product$ Identify in above reaction
→
The atomic number of an element is always equal to
→